Answer:
no maximum value
Explanation:
In order to maximize the value of p = 3x + 2y, we need to find the values of x and y that satisfy the following two conditions:
- The objective function p = 3x + 2y is maximized.
- The constraints on x and y are satisfied.
The constraints on x and y can be any set of inequalities that define the feasible region.
For example, the constraints could be:
x ≥ 0
y ≥ 0
To find the values of x and y that maximize p = 3x + 2y and satisfy the constraints, we can use the following steps:
First, find the partial derivatives of p = 3x + 2y with respect to x and y.
The partial derivatives of p = 3x + 2y with respect to x and y are:


Secondly Set the partial derivatives equal to zero and solve the system of equations.
Setting the partial derivatives equal to zero and solving the system of equations gives us:
3 = 0
2 = 0
Substitute the solutions for x and y into the objective function to find the maximum value of p.
This system of equations has no solutions, which means that there is no maximum value of p = 3x + 2y.
Note:
The objective function is unbounded, meaning that it can be made arbitrarily large.
One way to achieve this is to set x to a very large number and set y to zero.
This will give us a value of p that is equal to 3x.