Question

Is E correct?

Which of the following correctly describes the values of % AE and the E-factor for the reaction below? (% AE = percent atom economy; E-factor = environmental factor)


4 NH3 + 5 O2 → 4 NO + 6 H2O


A. % AE = 0; E-factor > 0


B. % AE = 100; E-factor > 0


C. % AE = 100; E-factor = 0


D. % AE < 100; E-factor = 0


E. % AE = 0; E-factor = 0

Answer 1

E %AE=0;E factor =0

Explanation