The final velocity of the ball at the end of 6 seconds is approximately 58.86 m/s.
Distance fallen (s) = (1/2) * acceleration (g) * time (t)^2
Final velocity (v) = initial velocity (u) + (acceleration * time)
Given that the ball is in free fall, its initial velocity (u) is 0, and the acceleration due to gravity (g) is approximately 9.81 m/s² (standard value on Earth).
Distance fallen (s):
s = (1/2) * g * t^2
s = (1/2) * 9.81 m/s² * (6 s)^2
s = (1/2) * 9.81 m/s² * 36 s²
s = 176.58 meters
So, the ball fell approximately 176.58 meters.
Final velocity (v):
v = u + (g * t)
v = 0 m/s + (9.81 m/s² * 6 s)
v = 58.86 m/s
The final velocity of the ball at the end of 6 seconds is approximately 58.86 m/s.