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If a rock is thrown downward with an initial speed of -6 m/s, then what is the rock's velocity after 4 seconds

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Answer:

-45.2m/s

Step-by-step explanation:

If a rock is thrown downward with an initial speed of -6 m/s (negative sign indicates the downward direction), we can calculate its velocity after 4 seconds using the equation for uniformly accelerated motion.

The equation for velocity in uniformly accelerated motion is:

Final Velocity = Initial Velocity + (Acceleration * Time)

In this case, the acceleration due to gravity is acting on the rock, and its value is approximately -9.8 m/s^2 (negative sign indicates the downward acceleration).

Let's calculate the velocity of the rock after 4 seconds:

Initial Velocity = -6 m/s

Acceleration = -9.8 m/s^2

Time = 4 seconds

Final Velocity = -6 m/s + (-9.8 m/s^2 * 4 s)

Final Velocity = -6 m/s - 39.2 m/s

Final Velocity = -45.2 m/s

answered
User Akshay Kalose
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