Question

{3x-4y=-10{6x+3y=-42

Answer 1

x=2,y=-20

Explanation:

3x-4y=-10

6x+3y=-42

multiply eq 1 by2

6x-8y=-20

6x+3y=-42

-11x=-22

divide both sides by -11

x=2

input int eq 2

6(2)+3y=-42

18+3y=-42

CLT

3y=-42+18

3y=-60

dbs by 3

y=-20

Answer 2

(- 6, - 2 )

Explanation:

given the 2 equations to solve simultaneously

3x - 4y = - 10 → (1)

6x + 3y = - 42 → (2)

multiplying (1) by - 2 and adding the result to (2) will eliminate x

- 6x + 8y = 20 → (3)

add (2) and (3) term by term to eliminate x

(6x - 6x) + (3y + 8y) = - 42 + 20, that is

0 + 11y = - 22

11y = - 22 ( divide both sides by 11 )

y = - 2

substitute y = - 2 into either of the original equations and solve for y

substituting into (1)

3x - 4(- 2) = - 10

3x + 8 = - 10 ( subtract 8 from both sides )

3x = - 18 ( divide both sides by 3 )

x = - 6

solution is (- 6, - 2 )