Question

A 260.mL sample of a 0.315M CaCl2 solution is left on a hot plate overnight; the following

morning the solution is 1.20M. What volume of water evaporated from the 0.315M CaCl2
solution?

Answer 1

Initial moles = 0.315 mol/L × 0.260 L

Final volume= (0.315 mol/L × 0.260 L)/1.20mol/L

Final Volume = 0.06825L.

Water evaporated = (initial V - final V)

= 0.260L - 0.06825L
= 0.19175L