Question

if you were the first mars explorer and discovered that when you dropped a hammer it took 0.68s to fall 0.90 m to the ground what would you calculate for the gravitational acceleration on mars?

Answer 1

Answer: 3.9 m/s²

Step-by-step explanation:

Given:

• Time taken for the hamster ball to fall: 0.68 seconds
• Distance travelled: 0.90 meters

To calculate the gravitational acceleration on Mars, we can use one of the kinematic equations:

`d = v_i t + (1)/(2) a t^2`

Where:

`d` represents the distance travelled (0.90 m),

`v_i` represents the initial velocity (which is zero when an object is dropped), and

`t` represents the time taken to fall (0.68 s).

By rearranging and solving for the acceleration (
`a`), we can calculate the gravitational acceleration on Mars.

`\begin{aligned}& 0.90=0+(1)/(2) g(0.68)^2 \\& (0.90 * 2)/((0.68)^2)=g \\& g=3.89 \approx 3.9 \mathrm{~m} / \mathrm{s}^2\end{aligned}`

Therefore, the gravitational acceleration on Mars is approximately 3.9 m/s²