Question

I have the vertex form quadratic equation: y = -3(x + 3)^2 + 4 and I am trying to turn it into Intercept form, how would I do that, In standard form it is y = 3x^2 - 18x - 23

Intercept form: a(x-p)(x-q)
Standard form: ax^2 + bx +c
Vertex form: a(x-h)^2 + k

Intercept form is a(x-(xint 1))(x-(xint2))

Answer 1

Hi,

if you know a²-b²=(a+b)(a-b), you may read the following.

Explanation:

`y=-3(x+3)^2+4\\\\y=-3(((x+3)^2-(3)/(4) )\\\\y=-3((x+3)+(√(3) )/(2) )((x+3)-(√(3) )/(2) )\\\\\boxed{y=-3(x+3+(√(3) )/(2) )(x+3-(√(3) )/(2) )}`