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7 Evaluate bda+c if a=−2 , b=3 , c=−12 , and d=− 3x-4/-2 +-12

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User Kaslico
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2 votes

Answer:

9x + 72.

Explanation:

To evaluate the expression bda + c using the given values for a, b, c, and d:

a = -2

b = 3

c = -12

d = (-3x - 4) / (-2) - 12

Now, substitute these values into the expression:

bda + c = 3 * (-2) * [(-3x - 4) / (-2) - 12] - 12

Let's simplify step by step:

1. Start with the expression:

bda + c = 3 * (-2) * [(-3x - 4) / (-2) - 12] - 12

2. Simplify within the brackets:

bda + c = 3 * (-2) * [(-3x - 4) / (-2)] - 3 * (-2) * 12 - 12

3. Cancel out -2 and 3 in the first term:

bda + c = -6 * [(-3x - 4) / (-2)] - 3 * (-2) * 12 - 12

4. Remove the negative signs in front of the fractions:

bda + c = 6 * [(3x + 4) / 2] - 3 * (-2) * 12 - 12

5. Distribute the 6 into the fraction:

bda + c = (6/2) * (3x + 4) - 3 * (-2) * 12 - 12

6. Simplify further:

bda + c = 3 * (3x + 4) + 72 - 12

7. Distribute the 3 into (3x + 4):

bda + c = 9x + 12 + 72 - 12

8. Combine like terms:

bda + c = 9x + 72

So, the value of bda + c when a = -2, b = 3, c = -12, and d = (-3x - 4) / (-2) - 12 is 9x + 72.

answered
User Georg Pfolz
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