Question

Rise to the run for each of the similar slope triang

numeric value. (Example 1)
1. AABC with vertices A (-6Ė-1) , B (-4Ė-1) ,
and C (-6Ė-3) ; ANLM with vertices N (-3Ė3) ,
L (0Ė3) , and M (-3Ė0)
-7-6-5-4-3-2
4
3
2
1
O
y
-2
-3
-4
1 x

Answer 1

To find the rise and run for each of the similar slope triangles, we can use the coordinates of the vertices.

First, let's calculate the rise and run for the triangle AABC.

Rise = change in y-coordinate = y₂ - y₁
Run = change in x-coordinate = x₂ - x₁

Using the coordinates:
A (-6, -1)
B (-4, -1)

Rise = -1 - (-1) = 0
Run = -4 - (-6) = 2

So, the rise to run ratio (slope) for triangle AABC is 0/2, which simplifies to 0.

Next, let's calculate the rise and run for the triangle ANLM.

Rise = change in y-coordinate = y₂ - y₁
Run = change in x-coordinate = x₂ - x₁

Using the coordinates:
N (-3, 3)
L (0, 3)

Rise = 3 - 3 = 0
Run = 0 - (-3) = 3

So, the rise to run ratio (slope) for triangle ANLM is 0/3, which simplifies to 0.

Therefore, the rise to run ratio (slope) for both triangles AABC and ANLM is 0.