Question

What are the roots of the function f(x) = (π^2-1/2) × x^π ×(1/π^2-π^2) with x € R? ​

Answer 1

To analyze the roots of the function f(X) =( π^2- 1/2 ) × x^π × (1/π^2-π^2),

let's set the function equal to zero and solve for x:

(π^2-1/2) × x^π × (1/π^^ 2-π^2) = 0

For the function to be equal to zero, at least one of the factors must be zero. LET'S EXAMINE Each factor separately:

This equation do not have real solutions. The Value of π is irrational, approximately equal to 3.14159, and π^2 is also an irrational number. TUS, π^2 - 1/2 is also an irrational number and cannot equal zero.

x^π = 0

for this factor to be zero, x must be zero.

1/π^2 - π^2 = 0

Therefore , the only real root of the function f(X) = (π^2-1/2) × x^π × (1/π^2-π^2) is x = >for more Similar Questions:

The only real root of the Function F(X) = (π^2-1/2) × x^π × (1 /π^2-π^2) is x = 0.

Answer 2

Draw X is greater than -3 and less than 6 on a number line