Question

Simplify the question, please help!

Answer 1

Step-by-step explanation:

Let's break it up:

`\sqrt[3]{27} \\\sqrt[3]{x^6}\\ \sqrt[3]{y^4}`

cube root of 27 is 3 since 3*3*3 = 27

cube root of
`x^6` is
`x^2` since
`x^2*x^2*x^2` =
`x^6`

cube root of
`y^4 = y\sqrt[3]{y}` since
`y^4=y*y*y*y` and since it is a cube root, we divide by three,
`y*y*y*y/3 = y` and
`y/3`

Final Answer:

`3x^2y\sqrt[3]{y}`