Question

F(x) = √6x

g(x) = √24x
Find (f g)(x). Assume x ≥ 0.
OA. (f g)(x) = 72x
OB. (f.g)(x) = 12x
OC. (f.g)(x) = 12√√
OD. (f.g)(x) = √30x
Finds (f • g)(x) assume x >0
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Answer 1

`f(x) = √(6x)`

`g(x) = √(24x)`

`f(g(x)) = f( √(24x) ) = \sqrt{6 √(24x) } = √(6) \sqrt{ √(24) } \sqrt{ √(x) } = √(6) \sqrt{2 √(6) } \sqrt{ √(x) } =`

`√(12) \sqrt{ √(6x) }`

The correct answer is C.

`f(x)g(x) = √(6x) √(24x) = 12x`