Question

a person takes a trip, driving with a constant speed of 92.0 km/h except for a 22.0-min rest stop. the person's average speed is 71.7 km/h. How much time is spent on the trip?

Answer 1

1.29 h

Step-by-step explanation:

We know that average speed = Total Distance/Total time

Then Given v(av) = 71.7 km/h

Let total time be T

He took a break of 22 min or 22/60 h

Eqn: for a constant velocity,

• vt = Distance where v = vel, t = time
• 92*t = S where t is total time exclusion of Resting time,

Also 71.7 = (92*(t)/(t - 22/60)

On Solving:

71.7(t-22/60) = 92t

92t - 71.7 t = 60t-22/60

• t = 1.29 h