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H(x)=x^2-2x-15/x^2-9 find zeros

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User Danimt
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1 Answer

5 votes

Answer: x = 5 and x = -3.

Explanation:

To find the zeros of the function H(x) = (x^2 - 2x - 15) / (x^2 - 9), we need to find the values of x that make the numerator equal to zero, since dividing by zero is undefined.

Step 1: Set the numerator equal to zero and solve for x:

x^2 - 2x - 15 = 0

Step 2: Factor the quadratic equation:

(x - 5)(x + 3) = 0

Step 3: Apply the zero product property:

x - 5 = 0 or x + 3 = 0

Step 4: Solve for x:

For x - 5 = 0, add 5 to both sides:

x = 5

For x + 3 = 0, subtract 3 from both sides:

x = -3

The zeros of the function H(x) are x = 5 and x = -3. These are the values of x that make the numerator equal to zero, and dividing by zero is undefined in this case.

answered
User ForEveR
by
8.8k points

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