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Answer:
a₂₀ = 67
Explanation:
the nth term of an arithmetic sequence is
= a₁ + (n - 1)d
a₁ is the first term , d the common difference , n the term number
here a₁ = 10 , d = a₂ - a₁ = 13 - 10 = 3 , and n = 20 , so
a₂₀ = 10 + (19 × 3) = 10 + 57 = 67