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Factoring simple trinomials

Factoring simple trinomials-example-1

1 Answer

1 vote

Answer:

(x-5)(x-6)= 20

x²-6x-5x+30=20

x²-11x+30-20=0

x²-11x+10=0

b²-4ac =(-11)²-4(1*10)= 81

Δ is strictly positive, the equation x²−11x+10=0 admits two solutions.

(-b-√Δ)/2a =(11-9)/2 =1

(-b+√Δ)/2a=(11+9)/2=10

solution (1,10)

x= 10inches

original image area: 10²=100inches

answered
User Kyaw Zin Htun
by
7.9k points
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