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How much impulse stops a 52-kg carton sliding at 4.0 m/s when it meets a rough surface?
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How much impulse stops a 52-kg carton sliding at 4.0 m/s when it meets a rough surface?
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May 1, 2024
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How much impulse stops a 52-kg carton sliding at 4.0 m/s when it meets a rough surface?
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Answer:
208 N * s
Step-by-step explanation:
Δp = m * ΔV
Δp = 52 * (4 - 0)
Δp = 208 N * s
Narkha
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May 5, 2024
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