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At a given volume of gas with a temperature of 100 K and a pressure of 225 kPa, what will be the pressure of the gas when the temperature is increased?

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User Aroldo
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Final answer:

The final pressure of the gas will increase with an increase in temperature, according to Gay-Lussac's law. Given initial pressure and temperature, if we know the final temperature we can use the formula P₁/T₁ = P₂/T₂ to calculate the final pressure.

Step-by-step explanation:

According to Gay-Lussac's law, for a given volume of gas at constant volume, the pressure is directly proportional to its absolute temperature. If the temperature of the gas increases the pressure also increases assuming the volume remains constant. Therefore, when the temperature of the gas is increased from 100 K to a higher value, the pressure of the gas will also increase.

The exact value of the new pressure can be determined by using the given initial temperature and pressure, as well as the new temperature. Considering the initial conditions of pressure (P₁=225 kPa) and temperature (T₁=100K) and not knowing the final temperature (T₂), we are unable to calculate the final pressure (P₂) at this stage. However, if the final temperature were provided, the final pressure could be calculated using the formula P₁/T₁ = P₂/T₂.

Learn more about Gay-Lussac's Law

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User Tom Prats
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