Question

The sum of two consecutive integers is at most 223. what is the largest possible integer?

Answer 1

Explanation:

Let's call the two consecutive integers x and (x + 1), where x is the smaller integer.

The sum of these two consecutive integers is given as:

x + (x + 1)

To find the largest possible integer, we need to maximize the value of x while ensuring that the sum is at most 223.

So, we have the inequality:

2x + 1 ≤ 223

Subtract 1 from both sides:

2x ≤ 222

Now, divide by 2:

x ≤ 111

Since x must be an integer (as stated in the problem), the largest possible integer for x is 111. Therefore, the largest possible integer is 111, and the consecutive integer would be 112 (111 + 1).