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Write any four solutions for the equation 3x+4y=14...​

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User Pklimczu
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Final answer:

Four solutions of the equation 3x+4y=14 are (0, 3.5), (2, 2), (4, 0.5), and (-2, 5). Each of these pairs, when substituted into the equation, will satisfy or 'solve' the equation.

Step-by-step explanation:

The question is asking for four solutions to the linear equation 3x + 4y = 14. That means we need to find pairs of x and y values that, when substituted into the equation, will hold the equation true. These pairs are called solutions because they 'solve' the equation.

  1. If we choose x=0, substituting this into the equation, we get 4y = 14, so y = 3.5. That gives us one solution: (0, 3.5).
  2. If we choose x=2, 3*2+4y=14 simplifies to 6+4y = 14. From here, we can get y = 2. So another solution is (2, 2).
  3. If x=4, then 3*4+4y = 14 simplifies to 12+4y = 14, so y = 0.5. Another solution is (4, 0.5).
  4. If x=-2, then 3*-2+4y=14 simplifies to -6+4y=14, so y = 5. So the last solution is (-2,5).

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