Answer:
The net ionic equation for the precipitation of lead(II) bromide (PbBr2) from aqueous solution can be written as follows:
Pb²⁺(aq) + 2Br⁻(aq) → PbBr2(s)
In this equation:
- Pb²⁺ represents the lead(II) ion in aqueous solution.
- 2Br⁻ represents two bromide ions in aqueous solution.
- PbBr2(s) represents the solid lead(II) bromide that forms as a precipitate when the two ions react.
This net ionic equation shows the essential chemical species involved in the precipitation reaction, focusing on the ions that participate in forming the solid product.