Question

A mixture of water and syrup is heated to 212°F to make syrup. It is allowed to cool in a room whose temperature is 59°F. The syrup cools to 180°F in 20 minutes. What will the temperature of the syrup be after 80 minutes? Round your answer to the nearest whole number.

A. 116.43°F B. 116.90°F C. 117.82°F D. 118.85°F​

Answer 1

To determine the temperature of the syrup after 80 minutes, we can use the concept of cooling or heating rates.

From the given information, we know that the syrup cools from 212°F to 180°F in 20 minutes.

To find the cooling rate, we can calculate the change in temperature per minute:

Change in temperature = (Initial temperature - Final temperature) / Time

Change in temperature = (212°F - 180°F) / 20 minutes = 32°F / 20 minutes = 1.6°F/minute

Now, we can use this cooling rate to find the temperature of the syrup after 80 minutes.

Change in temperature = Cooling rate * Time

Change in temperature = 1.6°F/minute * 80 minutes = 128°F

To find the final temperature, we subtract the change in temperature from the initial temperature:

Final temperature = Initial temperature - Change in temperature

Final temperature = 212°F - 128°F = 84°F

Therefore, the temperature of the syrup after 80 minutes will be approximately 84°F when rounded to the nearest whole number.

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