Question

If an object is moving with a constant velocity of 920 cm/s and starts at an initial position of 10 cm at t=0, what will be the position at t=0.4s?

Answer 1

378 cm

Step-by-step explanation:

Given:

x₀ = 10 cm

u = 920 cm/s

a = 0 cm/s²

t = 0.4 s

Find: x

x = x₀ + v₀ t + ½ at²

x = (10) + (920) (0.4) + ½ (0) (0.4)²

x = 378 cm