Question

A jet plane flying at a speed of 900 km/h pulls out of a vertical dive by turning upward along a circular path. What is the smallest radius of the circle such that the acceleration of the pilot does not exceed 8.00 g, where g = 9.80 m/s2

Answer 1

797 m

Step-by-step explanation:

First, convert the speed to m/s.

900 km/h = 250 m/s

Use centripetal acceleration to solve for the radius.

a = v² / r

8.00 (9.80 m/s²) = (250 m/s)² / r

r = 797 m