Question

\[2\^{\Large 3x+5}=64\^{\Large x-7}\]

Answer 1

assuming we're solving for "x".

`2^( 3x+5)=64^( x-7)\implies 2^( 3x+5)=(2^6)^( x-7)\implies 2^( 3x+5)=2^( 6(x-7)) \\\\\\ 3x+5=6(x-7)\implies 3x+5=6x-42\implies 5=3x-42 \\\\\\ 47=3x\implies \cfrac{47}{3}=x`