Answer:
To find the equation of a line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we can use the given slope and point.
Given slope (m) = 2 and the point (-4, 2), we can substitute these values into the slope-intercept form equation:
y = mx + b
2 = 2(-4) + b
Simplifying further:
2 = -8 + b
To solve for b, we can add 8 to both sides of the equation:
2 + 8 = -8 + b + 8
10 = b
Now that we have the value of b, we can write the equation in slope-intercept form:
y = 2x + 10
So, the equation in slope-intercept form for the line with a slope of 2 that passes through the point (-4, 2) is y = 2x + 10.