Question

The vertex of y=x^2+5 and it’s vertex form

Answer 1

The vertex form is y = (x-0)^2+5

The vertex is located at (0,5)

This is the lowest point on the parabola.

The general vertex form is y = a(x-h)^2 + k where (h,k) is the vertex.

If a > 0, then (h,k) is the lowest point on the parabola.

If a < 0, then (h,k) is the highest point on the parabola.