Question

Someone plss help me on this!! Thanks

Answer 1

`\textit{Law of Sines} \\\\ \cfrac{\sin(\measuredangle A)}{a}=\cfrac{\sin(\measuredangle B)}{b}=\cfrac{\sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\sin( C )}{37}=\cfrac{\sin( 30^o )}{19}\implies 19\sin(C)=37\sin(30^o) \implies \sin(C)=\cfrac{37\sin(30^o)}{19} \\\\\\ C=\sin^(-1)\left( ~~ \cfrac{37\sin( 30^o)}{19} ~~\right)\implies C\approx 77^o`

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