Question

If an object is ejected downward at 58.9 m/s and has fallen for 3 s, how far did it travel from when it was eiected?

Answer 1

y = 220.8 m

Step-by-step explanation:

y = v₀t + 1/2at²

y = -58.9*3 - 1/2 *9.8*3²

y = -176.7 - 44.1

y = 220.8m