Answer:
The sum of the stoichiometric coefficients of the products in the complete combustion reaction of pentane (C5H12) is:
The balanced equation for the complete combustion of pentane is:
C5H12 + 8O2 → 5CO2 + 6H2O
From the balanced equation, we can see that there are 5 moles of carbon dioxide (CO2) and 6 moles of water (H2O) produced for every 1 mole of pentane (C5H12) that reacts.
Therefore, the sum of the stoichiometric coefficients of the products is 5 + 6 = 11.
In other words, when 1 mole of pentane undergoes complete combustion, it produces 5 moles of carbon dioxide and 6 moles of water, giving a total of 11 moles of products.
Step-by-step explanation: