Question

a cheetah accelerates to a velocity of 7.8m/s during 5.4s. the cheetahs displacement during the acceleration was 22 meters. what was its initial velocity in m/s

Answer 1

0.35 m/s

Step-by-step explanation:

Given:

s = 22 m

v = 7.8 m/s

t = 5.4 s

Find: u

s = ½ (u + v) t

22 = ½ (u + 7.8) (5.4)

u = 0.35 m/s