Answer:
6 years
Explanation:
Let X be the car's value, and X(t) is the car's value as a function of time, in years.
We are told that depreciation of $2,030 occurs every year. So we can write:
X(t) = $30,200 - (t)*($2,030), where t = 0 when the car had a value of $30,200.
To find how many years until the car's value reaches $18,020, set X(t) to $18,020 and solve the equation for t:
X(t) = $30,200 - (t)*($2,030)
$18,020 = $30,200 - (t)*($2,030)
$30,200 - (t)*($2,030) = $18,020
- (t)*($2,030) = $18,020 - $30,200
- (t)*($2,030) = - $12,180
-t = - $12,180/($2,030)
t = 6 years