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if 79.0 L of helium at 27.0 degrees celsius is compressed to 32.0 L at constant pressure, what is the new temperature

asked
User Jack M
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6.9k points

1 Answer

1 vote
To find the new temperature, we can use the combined gas law equation: (P1 * V1) / T1 = (P2 * V2) / T2.

Given:
P1 = pressure at the initial state (constant pressure)
V1 = volume at the initial state (79.0 L)
T1 = temperature at the initial state (27.0 degrees Celsius)
V2 = volume at the final state (32.0 L)

We need to solve for T2, the new temperature.

Using the formula and plugging in the values:
(P1 * V1) / T1 = (P2 * V2) / T2

Since the pressure is constant, we can simplify the equation to:
(V1 / T1) = (V2 / T2)

Now we can solve for T2:
T2 = (V2 * T1) / V1

Plugging in the values:
T2 = (32.0 L * 27.0 degrees Celsius) / 79.0 L

Answer: Calculating this, we find that the new temperature is approximately 10.95 degrees Celsius.
answered
User MTarantini
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7.8k points

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