Question

A glass vessel contains air at 27°C, the temperature to which it must be heated so that one-fourth of air is expelled from it at constant pressure is

47°C, 77°C, 102°C, and 127°C?​

Answer 1

127 C

Step-by-step explanation:

Ideal gas law:

PV = nRT,

where P is the absolute pressure,

V is the volume,

n is the amount of gas,

R is the universal gas constant,

and T is the absolute temperature.

The pressure and volume are constant.

P₁V₁ = P₂V₂

Therefore:

n₁T₁ = n₂T₂

Plugging in:

n (27 + 273) K = (3n/4) T

T = 400 K

T = 127 C