Question

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Answer 1

`√(60x^2y)`

Explanation:

using the rule of radicals

•
`√(abc)` ⇔
`√(a)` ×
`√(b)` ×
`√(c)`

consider

`√(60x^2y)`

=
`√(60)` ×
`√(x^2)` ×
`√(y)`

=
`√(4(15))` × x ×
`√(y)`

=
`√(4)` ×
`√(15)` × x ×
`√(y)`

= 2 ×
`√(15)` × x ×
`√(y)`

= 2x ×
`√(15)` ×
`√(y)`

= 2x ×
`√(15y)`

= 2x
`√(15y)`