Final answer:
The Sun's position at noon on June 21 (the summer solstice) in a city located at 50°N latitude is approximately 67° above the horizon. Taking into account the options provided in the question, the closest correct answer would be (d) 70°.
Step-by-step explanation:
In order to answer your question about the sun's position at noon on June 21 at a city located at 50°N, let's first understand some basic principles. On Earth's equator, the celestial equator passes through zenith, the point directly overhead. This means, on March 21 when the Sun crosses the celestial equator, it should be at the zenith, or 90°. However, on June 21, the Sun is 23° north of the celestial equator, and hence, 23° away from the zenith at noon. Consequently, the altitude above the horizon is 90° (zenith's altitude) minus 23°, which is 67° above the horizon.
If you were to measure this at the winter solstice, the sun would be about 23° south of the celestial equator. From the Tropic of Cancer (23° N), the zenith would be at 23º N. Hence the Sun would be 46° away from the zenith resulting in an altitude of 90° - 46° = 44°. So the answer to your question about the sun's position at noon on June 21 in a city located at 50°N is approximately 67°, so option (d) 70° may be considered the closest correct answer.
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