asked 23.2k views
2 votes
Determine the total number of roots of each polynomial function using the factored form. f(x)=(x-6)^2(x+2)^2

asked
User Goutham
by
8.5k points

1 Answer

6 votes

Answer: To determine the total number of roots of the polynomial function f(x) = (x - 6)^2(x + 2)^2, we can look at the powers of the factors in the factored form.

The power of a factor in the factored form represents the multiplicity of the corresponding root. The multiplicity of a root indicates how many times the root appears in the factored form.

In this case, the factor (x - 6) has a power of 2, and the factor (x + 2) also has a power of 2. This means that both the roots x = 6 and x = -2 have a multiplicity of 2.

The total number of roots of a polynomial function is equal to the sum of the multiplicities of all its distinct roots.

In this polynomial function, the root x = 6 has a multiplicity of 2, and the root x = -2 also has a multiplicity of 2. Therefore, the total number of roots is 2 + 2 = 4.

So, the correct answer is that the polynomial function f(x) = (x - 6)^2(x + 2)^2 has a total of 4 roots.

answered
User Shaya
by
7.9k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.