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Answer: 393.6 grams of oxygen in 615 g of Li₂O.
Explanation: (615 g of Li₂O) * (1 mole of Li₂O / 74.0 g of Li₂O) * (16.0 g of oxygen / 1 mole of oxygen) = 393.6 grams of oxygen.
Answer:
= 393.6g.
Step-by-step explanation:
check this I guess it will help.