Answer:
There ya go
Explanation:
To find the coordinates of point A, we know that the graph crosses the x-axis at (-7,0) and point A. Since the x-coordinate of point A is unknown, let's call it (x,0).
Since the graph crosses the y-axis at (0, -21), we can substitute these coordinates into the equation y = x² + ax + b to solve for a and b.
Substituting (0, -21) into the equation, we have:
-21 = 0² + a(0) + b
-21 = b
So now we have b = -21.
Next, we substitute (-7,0) into the equation:
0 = (-7)² + a(-7) + (-21)
0 = 49 - 7a - 21
0 = 28 - 7a
Simplifying further, we have:
7a = 28
a = 4
Now that we have the values of a and b, we can determine the coordinates of point A.
Substituting a = 4 and b = -21 into the equation, we have:
y = x² + 4x - 21
To find the x-coordinate of point A, we set y = 0:
0 = x² + 4x - 21
Factoring or using the quadratic formula, we find that the x-coordinate of point A is 3.
Therefore, the coordinates of point A are (3, 0).
To find the coordinates of the turning point, we can use the formula x = -b/2a. Plugging in a = 4 and b = -21, we have:
x = -4 / (2 * 4)
x = -1
Now, substitute x = -1 into the equation y = x² + 4x - 21 to find the y-coordinate of the turning point:
y = (-1)² + 4(-1) - 21
y = 1 - 4 - 21
y = -24
Therefore, the coordinates of the turning point are (-1, -24).
In summary:
(a) The coordinates of point A are (3, 0).
(b) The coordinates of the turning point are (-1, -24).