asked 11.1k views
5 votes
Consider the reaction A ? B. If, at equilibrium, the concentration of B is greater than the concentration of A, is the change in standard free energy (ΔG'o) of the reaction: a. Positive b. Negative c. Zero d. Cannot be determined from the information given.

asked
User Willmac
by
8.4k points

1 Answer

6 votes

Final answer:

For the reaction A → B at equilibrium with a higher concentration of B, the change in standard free energy (ΔG'u00b0) is negative because the reaction is spontaneous in the forward direction.

Step-by-step explanation:

In the context of the chemical reaction A → B at equilibrium, if the concentration of B is greater than the concentration of A, this implies that the equilibrium constant Keq is greater than one. According to the equation ΔG° = ΔH° - TΔS°, the standard free energy change (ΔG°) can be related to Keq. In general, if Keq > 1, then ΔG° is negative, indicating that the reaction is spontaneous in the forward direction under standard conditions. Thus, in this case, the change in standard free energy (ΔG'u00b0) of the reaction would be negative as the products are favored at equilibrium.

answered
User Wforl
by
8.1k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.