Question

what is an equation of the line that passes through the point (-3,1) and is perpendicular to the line x-3y=6

Answer 1

y= -x/3 + 2

Explanation:

x-3y=6 ------> y = x/3 -2

Make slope negative since its perpendicular: x/3 -> -x/3

Plug points + new slope into point-slope formula: (y - y) = m(x - x)

y-1 = -1/3(x+3) -> y = -x/3 + 2 (the answer)