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How many grams of calcium hydroxide would be required to completely react with a 22.5 mL solution of 39.0 % (by mass) acetic acid (density = 1.045 g/mL )?

asked
User Jatinder
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1 Answer

3 votes

Step-by-step explanation:

To calculate the grams of calcium hydroxide required, follow these steps:

1. Calculate the mass of acetic acid in the solution:

Mass(acetic acid) = Volume(solution) * Density(solution)

Mass(acetic acid) = 22.5 mL * 1.045 g/mL

2. Determine the mass of acetic acid in grams:

Mass(acetic acid) = Mass(acetic acid) * Percentage(concentration)

Mass(acetic acid) = 9.133 grams

3. Convert the mass of acetic acid to moles using its molar mass.

4. Use the balanced equation to determine the stoichiometric ratio between acetic acid and calcium hydroxide.

5. Calculate the moles of calcium hydroxide needed by dividing the moles of acetic acid by 2.

6. Finally, multiply the moles of calcium hydroxide by its molar mass to obtain the grams required.

By following these steps, you can determine the grams of calcium hydroxide needed for the reaction.

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User Flows
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