Question

Cuboidal cell

Cell A
Cell B
Cell C
Cell D
Side length (um)
2
4
6
8
Surface area of a cube: A = 6s²
Volume of a cube: V - s³
Using the information from the table, what is the surface-area-to-volume
ratio for the cuboidal cell that removes waste via diffusion most
efficiently?
um
-1

Answer 1

The surface-area-to-volume ratio for efficient waste removal via diffusion can be determined by comparing the surface area and volume of different cuboidal cells. Cell A has a surface-area-to-volume ratio of 3 um^(-1), Cell B has a ratio of 1.5 um^(-1), Cell C has a ratio of 1 um^(-1), and Cell D has a ratio of 0.75 um^(-1). Therefore, Cell A, with a ratio of 3 um^(-1), is the cell that removes waste via diffusion most efficiently.