Question

Solve the system of equations

2x+6y=-6, 4x-3y=-12
what is the solution to the system of equations

Answer 1

x = -3, y = 0

Explanation:

2x+6y=-6 equation1

4x-3y=-12 equation2

multiply equation2 by 2

2[ 4x-3y=-12]

8x - 6y = -24 equation3

add equations 1 & 3

2x+6y=-6

8x - 6y = -24

--------------------

10x = -30

x = -3

substitute x = -3 to any of the equations

I will use equation1

2x+6y=-6

2(-3) + 6y = -6

-6 + 6y = -6

6y = 0

y = 0

Answer 2

2x + 6y = -6 ...(1)

4x - 3y = -12 ...(2)

We can use the method of substitution or elimination to find the solution. I will use the method of substitution.

From equation (1), we can solve for x in terms of y:

2x = -6 - 6y

x = (-6 - 6y)/2

x = -3 - 3y

Now, substitute this value of x into equation (2):

4(-3 - 3y) - 3y = -12

-12 - 12y - 3y = -12

-15y = 0

y = 0

Substitute this value of y back into equation (1) to find x:

2x + 6(0) = -6

2x = -6

x = -3

Therefore, the solution to the system of equations is x = -3 and y = 0.

hope this helps