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Can someone help me?​-example-1

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Answer:

K equivalence R

This is a simple equivalence (also known as biconditional) between K and R.

The truth table for K equivalence R is as follows:

K R K ≡ R

0 0 1

0 1 0

1 0 0

1 1 1

KƆ (RƆP)

This expression seems to involve negation (Ɔ) and conjunction (K).

Let's break it down step by step:

RƆP: This is the negation of the conjunction of R and P.

KƆ (RƆP): This is the negation of the conjunction of K and the negation of (R and P).

The truth table for KƆ (RƆP) is as follows:

K R P RƆP KƆ (RƆP)

0 0 0 1 0

0 0 1 1 0

0 1 0 0 1

0 1 1 0 1

1 0 0 1 0

1 0 1 1 0

1 1 0 0 1

1 1 1 0 1

~P / ~R

This expression appears to be an implication where ~P is the antecedent and ~R is the consequent.

The truth table for ~P / ~R is as follows:

P R ~P ~R ~P / ~R

0 0 1 1 1

0 1 1 0 0

1 0 0 1 1

1 1 0 0 1

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User Gromiczek
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