Question

What is the equation for the line parallel to y = 8x + 13 that contains P(–7, –4)?

Answer 1

-33 and -11

Explanation:

As putting values in it.

Answer 2

↠ Answer:

y = 8x + 52

↠ Step-by-step explanation:

We're given the following conditions for a line's equation :

It passes through the point (-7,-4)

It's parallel to the line y = 8x + 13.

Parallel lines have the same slope. So, the new line has a slope of 8, just like y = 8x + 13. So now, all we need is our point-slope formula :

⇒
`\boldsymbol{y-y_1=m(x-x_1)}`

Substitute all the data :

• 
  `\boldsymbol{y-(-4)=8(x-(-7)}`
• 
  `\boldsymbol{y+4=8(x+7)}`
• 
  `\boldsymbol{y+4=8x+56}`
• 
  `\boldsymbol{y=8x+56-4}`
• 
  `\boldsymbol{y=8x+52}`

Therefore, the eqn. of the line is y = 8x + 52.