To find the value of x in this geometry problem, we can use the properties of parallel lines and corresponding angles.
Given:
ABC and DEF are straight lines (which means they are 180 degrees each).
AC is parallel to DF.
BE = CE.
We need to determine the value of x.
First, let's focus on the angles formed by these lines:
Angle ADC (the angle at point D) is 132°.
Angle EBC (the angle at point B) and Angle ECD (the angle at point C) are equal because BE = CE.
Now, let's use the fact that AC is parallel to DF:
Angle ADC (132°) and Angle ECD (the angle at point C) are corresponding angles, which means they are equal.
So, we have:
Angle ECD = 132°
Now, we know that the sum of angles around point C should be 360 degrees:
Angle EBC + Angle ECD + x = 360°
We already know that Angle ECD is 132°, and since BE = CE, Angle EBC must be equal:
Angle EBC = Angle ECD = 132°
Now, let's substitute these values into the equation:
132° + 132° + x = 360°
Combine like terms:
264° + x = 360°
Now, isolate x:
x = 360° - 264°
x = 96°
So, the value of x is 96 degrees.