Question

Find the perimeter of a rectangle with a width of 2x^2+4x-8 and a length of 3x+8.

A.2x^2+7x

B.4x^2+14x

C.4x^2+14x+32

C.18x^2

Answer 1

B . 4x^2 + 14x

Explanation:

2(2x^2+4x-8) + 2(3x+8)

=4x^2 +8x-16+6x+16

=4x^2+14 (ans)