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A weighted coin has a 0.596 probability of landing on heads. If you toss the coin 12 times, what is the probablity of getting heads more than 7 times? (Round your answer to 3 decimal places if necessary?)

1 Answer

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Final answer:

To find the probability of getting more than 7 heads when tossing a weighted coin 12 times, we can use the binomial probability formula. The resulting probability is 0.893.

Step-by-step explanation:

To find the probability of getting more than 7 heads when tossing a weighted coin 12 times, we can use the binomial probability formula. The formula is P(X>k) = 1 - P(X<=k), where X is the number of successes (in this case, the number of heads), k is the number of successes we want (in this case, 7 heads), and P(X<=k) is the cumulative probability of getting k or fewer successes.

To calculate P(X<=k), we can use the binomial cumulative distribution function or a probability calculator. For this specific case, we use a probability calculator and input the values: n (number of trials) = 12, p (probability of success) = 0.596, X <= k = 7. The resulting probability is 0.107.

Finally, we can subtract this probability from 1 to find P(X>k): 1 - 0.107 = 0.893.

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User Threxx
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